I introduce how to compare 2 sample proportions through the use of z-tests and confidence intervals. I finish with a 2 Sample Pooled z-test. EXAMPLES AT 11:09 21:28
I have added annotations to improve some of the language of my example.
Defining the variables
Pm: Population proportion of men snacking
Pw: Population proportion of women snacking
SRS is stated
Since 380(.608)=231.04, 380(1-.608)=148.96, 370(.53)=196.1, 370(1-.53)=173.9 are all greater than or equal to 5 the sampling distribution of the difference of sample proportions will be approximately Normal.
Independence: It is reasonable to assume each population of men and women are greater than ten times each sample size 10(380)=3800 and 10(370)=3700.
Conclusion: The observed difference of .078 or 7.8% or one more extreme has a p value of .03 which is less than our level of significance of .05 so we reject Ho. There is not enough evidence to conclude there is a difference in the snacking habits of men and women.
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