Solve math problems | Solving Similar Triangles | Word problems on Similarity Postulates
Similarity postulates AA SAS SSS
AAA similarity criterion
If two angles of one triangle are respectively equal to two angles of another triangle, then the two triangles are similar.
SSS (Side–Side–Side) similarity criterion for two triangles
If in two triangles, sides of one triangle are proportional to (i.e., in the same ratio of ) the sides of the other triangle, then their corresponding angles are equal and hence the two triangles are similiar.
SAS (Side–Angle–Side) similarity criterion for two triangles
If one angle of a triangle is equal to one angle of the other triangle and the sides including these angles are proportional, then the two triangles are similar
00:01 Q10. CD and GH are respectively the bisectors of triangle ACB and triangle EGF such that D and H lie on sides AB and FE of angle ABC and angle EFG respectively. If triangle ABC ~ triangle FEG, show that:
00:39 (i) CD/GH = AC/FG 04:41 (ii) triangle DCB ~ triangle HGE 06:23 (iii) triangle DCA ~ triangle HGF
01:51 Angular bisector
06:08 Use AA similarity criterion
07:25 Q11. In Fig. 6.40, E is a point on side CB produced of an isosceles triangle ABC with AB = AC. If AD perpendicular to BC and EF perpendicular to AC, prove that triangle ABD ~ triangle ECF.
09:32 Property of isosceles triangle
10:04 AA similarity criterion
10:44 Q12. Sides AB and BC and median AD of a triangle ABC are respectively proportional to sides PQ and QR and median PM of triangle PQR (see Fig. 6.41). Show that triangle ABC ~ triangle PQR.
12:42 SAS (Side–Angle–Side) similarity criterion
14:20 Q13. D is a point on the side BC of a triangle ABC such that ? ADC = ? BAC. Show that CA^2 = CB.CD.
15:45 Use AA similarity criteria
16:58 Similar Triangles word problems
Q15. A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.
19:57 Q16. If AD and PM are medians of triangles ABC and PQR, respectively where triangle ABC ~ triangle PQR, prove that AB/PQ = AD/PM
Triangles class 10
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