Common core math Trigonometry Functions | Solving trigonometric ratios of complementary angles

http://www.learncbse.in/ncert-class-10-math-solutions/

http://www.learncbse.in/ncert-solutions-for-class-10-maths-chapter-8-introduction-to-trigonometry/

http://www.learncbse.in/rd-sharma-class-10-solutions-chapter-5-trigonometric-ratios/

00:02 CBSE class 10 maths NCERT SolutionsChapter 8 Trigonometry Exercise 8.3 Q1. Solving Problems using trigonometric ratios of complementary angles

00:18 (i) sin 18° / cos 72° || 01:42 (ii) tan 26° / cot 64° || 03:07 (iii) cos 48° – sin 42° || 04:25 (iv) cosec 31° – sec 59°

00:36 COMPLEMENTARY ANGLES DEFINATION

Two angles are said to be complementary if their sum equals 90° pair of complementary angles A and (90° – A).

make same numerator & denominator by using the trigonometric ratios of complementary angles relationship.

sin (90°– A) = cos A, cos (90°– A) = sin A

05:42 2. Show that :

06:11 Prove the trigonometric equation (i) tan 48° tan 23° tan 42° tan 67° = 1

06:28 consider LHS of trigonometric equation.

07:28 complementary angles are defined pair of two angles whose as sum equals 90°.

08:05 Important property

If A and B are complementary angles then Tan A * Tan B = 1.

09:51 (ii) cos 38° cos 52° – sin 38° sin 52° = 0

10:51 Trigonometric Ratios of Complementary Angle - Solving Problems

sin (90° – A) = cos A, cos (90° – A) = sin A ,

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