2003-ap-calculus-frq-free-response-question-ab-bc-6-let-f-be-the-function-defined-by-is-f-continuou

# Interactive video lesson plan for: 2003 ap calculus frq free response question ab bc #6 Let f be the function defined by is f continuou

#### Activity overview:

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Question S

f be the function defined by

f(~+1 for 0 3
f(~ 1 5 - ~ for 3 5,
Is f continuous at ~ - 3? ~xplain why or why not.
Find the average value of f(~) on the closed interval O 5.
Suppose the function g is defined by ~
| k~~ + 1 for 0 3
9(~ . mx + 2 for 3 5,
where k and m are constants. If g is ~ifferentiable at ~ - 3, what

Let
(a)
(b)
(c)

are the values of and m

(a) f is continuous at x - 3 because
lim f(x) - lim f(~) - 2-
x~3- x~3+
Therefore, ~~ f(~) - 2 - f(3),

1 answers "yes" and equates the

values of the left- and right-hand
2
limits

1 explanation involving limits

(b)

antiderivative of ~~
antiderivative of 5 - ~

2k - 3m + 2
k ~
-- 'III
4
values for k an

(c)

2.

Since g is continuous at ~ - 3, 2k - 3m +

k for O ~ 3
g'(x) 2 x +~
m for 3 ~ 5

xlim~3_ g'(~ 4-k and ~1~3+m 9~ - m

Since these two limits exist and g is
differentiable at x - 3 the two limits are
equal, Thus k - m.

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