# Interactive video lesson plan for: Common core math Trigonometry Functions | Solving trigonometric ratios of complementary angles

#### Activity overview:

Common core math Trigonometry Functions | Solving trigonometric ratios of complementary angles

http://www.learncbse.in/ncert-class-10-math-solutions/
http://www.learncbse.in/ncert-solutions-for-class-10-maths-chapter-8-introduction-to-trigonometry/
http://www.learncbse.in/rd-sharma-class-10-solutions-chapter-5-trigonometric-ratios/

00:02 CBSE class 10 maths NCERT SolutionsChapter 8 Trigonometry Exercise 8.3 Q1. Solving Problems using trigonometric ratios of complementary angles
00:18 (i) sin 18° / cos 72° || 01:42 (ii) tan 26° / cot 64° || 03:07 (iii) cos 48° – sin 42° || 04:25 (iv) cosec 31° – sec 59°
00:36 COMPLEMENTARY ANGLES DEFINATION
Two angles are said to be complementary if their sum equals 90° pair of complementary angles A and (90° – A).
make same numerator & denominator by using the trigonometric ratios of complementary angles relationship.
sin (90°– A) = cos A, cos (90°– A) = sin A
05:42 2. Show that :
06:11 Prove the trigonometric equation (i) tan 48° tan 23° tan 42° tan 67° = 1
06:28 consider LHS of trigonometric equation.
07:28 complementary angles are defined pair of two angles whose as sum equals 90°.
08:05 Important property
If A and B are complementary angles then Tan A * Tan B = 1.
09:51 (ii) cos 38° cos 52° – sin 38° sin 52° = 0
10:51 Trigonometric Ratios of Complementary Angle - Solving Problems
sin (90° – A) = cos A, cos (90° – A) = sin A ,

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learncbse.in
CBSE solutions for class 10 maths Chapter 8 Trigonometry Exercise 8.4
CBSE class 10 maths NCERT SolutionsChapter 8 Trigonometry Exercise 8.2 | Trigonometric Identities
CBSE class 10 maths NCERT Solutions Chapter 8 Trigonometry
Solutions for CBSE class 10 Maths Trigonometry
NCERT solutions for class 10 maths Trigonometry
NCERT solutions for CBSE class 10 maths Trigonometry
CBSE class 10 maths Trigonometry
Common core Math Trigonometry

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