trigonometric-ratios-of-complementary-angle-solving-problems-basics-of-complementary-angles

Trigonometric Ratios of Complementary Angle - Solving Problems | Basics of Complementary Angles

http://www.learncbse.in/ncert-class-10-math-solutions/

http://www.learncbse.in/ncert-solutions-for-class-10-maths-chapter-8-introduction-to-trigonometry/

http://www.learncbse.in/rd-sharma-class-10-solutions-chapter-5-trigonometric-ratios/

This tutorial shows how to solve trigonometric equation involving Complementary angles. Concepts that are reviewed during this tutorial include:

Combining like terms.

solving equation involving raducals.

Complementary angles

In this video we solve a trigonometric expression by using trigonometric ratios of complementary angles. This is really simple and detail tutirial covers the entire topic complementary angles - trigonometric ratios. In such problems we have to make same numerator & denominator by using the trigonometric ratios of complementary angles relationship.From Complementary Angle Theorem

00:02 CBSE solutions for class 10 maths Chapter 8 Trigonometry q1. Solving Problems using trigonometric ratios of complementary angles

00:18 (i) sin 18° / cos 72° || 01:42 (ii) tan 26° / cot 64° || 03:07 (iii) cos 48° – sin 42° || 04:25 (iv) cosec 31° – sec 59°

00:36 COMPLEMENTARY ANGLES DEFINATION

Two angles are said to be complementary if their sum equals 90° pair of complementary angles A and (90° – A).

make same numerator & denominator by using the trigonometric ratios of complementary angles relationship.

sin (90°– A) = cos A, cos (90°– A) = sin A

05:51 (ii) cos 38° cos 52° – sin 38° sin 52° = 0

5:53 Trigonometric Ratios of Complementary Angle - Solving Problems

sin (90° – A) = cos A, cos (90° – A) = sin A ,

07:15 CBSE solutions for class 10 maths Chapter 8 Trigonometry q3. If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A.

07:26 Trigonometric Ratios of Complementary Angle- Find the Angle Problems

08:00 use rigonometric ratios of complementary angle

tan (90° – A) = cot A, cot (90° – A) = tan A,

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