CBSE class 10 maths NCERT Solutions chapter 6 Triangles Exercise 6.3 | Math tutorials Similar Triangles

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00:03 CBSE class 10 maths NCERT Solutions chapter 6 Triangles Q1. State which pairs of triangles in Fig. 6.34 are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form :

00:47 Tests for Similar Triangles AA similarity criterion

01:18 (ii) | 02:58 (iii) | 03:59 (iv) | 04:54 (v) | 06:10 (vi) |

02:17 Solving similar triangles SSS (Side–Side–Side) similarity criterion

05:43 SAS (Side–Angle–Side) similarity criterion for two triangles

06:36 Angle sum prpperty of triangle.

07:22 Solving similar triangles AA similarity criterion

07:47 CBSE class 10 maths NCERT Solutions chapter 6 Triangles Q3. Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at the point O. Using a similarity criterion for two triangles, show that OA/OC = OB/OD.

08:16 constructions procedure to solve geometry problems

09:20 Vertically opposite angles are equal

09:33 Alrenate interior angles

10:18 AAA similarity criterion

11:05 CBSE class 10 maths NCERT Solutions chapter 6 Triangles Q4. In Fig. 6.36, QR/QS = QT/PR and angle 1 = angle 2. Show that triangle PQS ~ triangle TQR.

12:01 It tow angles are equal then their sides opposite to equal angles are equal.

13:55 SAS (Side–Angle–Side) similarity criterion for two triangles

14:14 CBSE class 10 maths NCERT Solutions chapter 6 Triangles Q5. S and T are points on sides PR and QR of triangle PQR such that angle P = angle RTS. Show that triangle RPQ ~ triangle RTS.

16:08 AAA similarity criterion

16:38 CBSE class 10 maths NCERT Solutions chapter 6 Triangles Q6. In Fig. 6.37, if triangle ABE ~ triangle ACD, show that triangle ADE ~ triangle ABC.

18:33 SAS (Side–Angle–Side) similarity criterion

19:30 CBSE class 10 maths NCERT Solutions chapter 6 Triangles Q7. In Fig. 6.38, altitudes AD and CE of triangle ABC intersect each other at the point P. Show that:

20:33 (i) triangle AEP ~ triangle CDP

21:13 Vertically opposite angles are equal

22:08 (ii) triangle ABD ~ triangle CBE

22:52 use AAA similarity criterion

23:37 (iii) triangle AEP ~ triangle ADB

25:03 AAA similarity criterion

25:35 (iv) triangle PDC ~ triangle BEC

26:18 AA similarity criterion

26:38 Q8. E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that triangle ABE ~ triangle CFB.

28:52 Apply AA similarity criterion.

29:41 Q9. In Fig. 6.39, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that:

30:08 (i) triangle ABC ~ triangle AMP 31:22 (ii) CA/PA = BC/MP.

31:49 CBSE class 10 maths NCERT Solutions chapter 6 Triangles Q10. CD and GH are respectively the bisectors of triangle ACB and triangle EGF such that D and H lie on sides AB and FE of angle ABC and angle EFG respectively. If triangle ABC ~ triangle FEG, show that:

34:04 (i) CD/GH = AC/FG 36:36 (ii) triangle DCB ~ triangle HGE 38:20 (iii) triangle DCA ~ triangle HGF

33:19 Angular bisector

35:28 Use AA similarity criterion

39:16 CBSE class 10 maths NCERT Solutions chapter 6 Triangles Q11. In Fig. 6.40, E is a point on side CB produced of an isosceles triangle ABC with AB = AC. If AD perpendicular to BC and EF perpendicular to AC, prove that triangle ABD ~ triangle ECF.

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CBSE solutions for class 10 maths Chapter 6 Triangles Exercise 6.3

CBSE class 10 maths NCERT Solutions chapter 6 Triangles

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