Find the Angle using Trigonometric Ratios of Complementary Angles

http://www.learncbse.in/ncert-class-10-math-solutions/

http://www.learncbse.in/ncert-solutions-for-class-10-maths-chapter-8-introduction-to-trigonometry/

http://www.learncbse.in/rd-sharma-class-10-solutions-chapter-5-trigonometric-ratios/

In this video we solve a trigonometric expression by using trigonometric ratios of complementary angles. This is really simple and detail tutirial covers the entire topic complementary angles - trigonometric ratios. In such problems we have to make same numerator & denominator by using the trigonometric ratios of complementary angles relationship.From Complementary Angle Theorem

sin (90° – A) = cos A, cos (90° – A) = sin A ,

tan (90° – A) = cot A, cot (90° – A) = tan A,

sec (90° – A) = cosec A, cosec (90° – A) = sec A,

00:02 CBSE class 10 maths NCERT SolutionsChapter 8 Trigonometry Exercise 8.3 Q3. If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A.

00:20 Trigonometric Ratios of Complementary Angle- Find the Angle Problems

00:45 use rigonometric ratios of complementary angle

tan (90° – A) = cot A, cot (90° – A) = tan A,

00:28 CBSE class 10 maths NCERT SolutionsChapter 8 Trigonometry Exercise 8.3 Q4. If tan A = cot B, prove that A + B = 90°.

03:05 trigonometric ratios of complementary angle

cot (90° – A) = tan A, tan (90° – A) = cot A,

04:02 CBSE class 10 maths NCERT SolutionsChapter 8 Trigonometry Exercise 8.3 Q5. If sec 4A = cosec (A – 20°), where 4A is an acute angle, find the value of A.

04:56 trigonometric ratios of complementary angle, sec (90° – A) = cosec A, cosec (90° – A) = sec A,

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