NCERT solutions for CBSE class 10 maths Chapter 8 Trigonometry Ex 8.1

http://www.learncbse.in/ncert-class-10-math-solutions/

http://www.learncbse.in/ncert-solutions-for-class-10-maths-chapter-8-introduction-to-trigonometry/

http://www.learncbse.in/rd-sharma-class-10-solutions-chapter-5-trigonometric-ratios/

00:02 CBSE solutions for class 10 maths Chapter 8 Trigonometry Exercise 8.1 q8. If 3 cot A = 4, check whether (1-tan²A)/(1+tan²A) = cos²A - sin²A or not.

00:48 Take LHS of trigonometric equation

00:20 The ratios cosec A, sec A and cot A are respectively, the reciprocals of the ratios sin A, cos A and tan A

02:28 Take RHS of trigonometric equation

02:53 Apply Trigonometric Ratio

tangent of angle theta = side opposite to angle theta / side adjacent to angle theta.

03:31 Pythagoras Theorem

In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

04:01 cosine of angle theta = side adjacent to angle theta / hypotenuse

Remember as ' CAH ' Cosine equals Adjacent over Hypotenus.

04:20 consider Trigonometric Ratio

sine of angle theta = side opposite to angle theta / hypotenuse

sin is equal to opposite over hypotenuse.

Remember as ' SOH '

04:39 solve trigonometric equation

05:31 CBSE solutions for class 10 maths Chapter 8 Trigonometry Exercise 8.1 q9. In triangle ABC, right-angled at B, if tan A = 1/ sqrt (3) : find the value of:

(i) sin A cos C + cos A sin C (ii) cos A cos C – sin A sin C

06:06 Naming the sides | Determining the sides of right angles triangles using Trigonometric Ratio Tan.

07:08 tangent of angle theta = side opposite to angle theta / side adjacent to angle theta.

Remeber as ' TAO '. Tan is adjacent over Opposite.Remember as ' TAO '

08:00 Pythagoras LAW

10:08 (i)

11:28 (ii)

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