Trigonometry ratios Lessons-Definitions | Basic Trigonometric Ratios (Solved problems)

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http://www.learncbse.in/ncert-solutions-for-class-10-maths-chapter-8-introduction-to-trigonometry/

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00:04 CBSE class 10 maths NCERT Solutions Trigonometry Exercise 8.1 Q1. In triangle ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine

(i) sin A, cos A 003:00 (ii) sin C, cos C

00:25 Naming the sides | Finding sides of right triangle.

00:45 Pythagoras Theorem

01:40 Trigonometric Ratio Defination

sine of angle theta = side opposite to angle theta / hypotenuse

sin is equal to opposite over hypotenuse.

Remember as ' SOH '

02:15 cosine of angle theta = side adjacent to angle theta / hypotenuse

Remember as ' CAH ' Cosine equals Adjacent over Hypotenus.

03:54 CBSE class 10 maths NCERT Solutions Trigonometry Exercise 8.1 Q2. In Fig. 8.13, find tan P – cot R.

04:08 Finding the sides of right triangle

04:31 Pythagoras Theorem

05:30 Tangent of angle theta = side opposite to angle theta / side adjacent to angle theta.Remeber as ' TAO '. Tan is adjacent over

06:18 cotangent of angle theta = side adjacent to angle theta / side opposite to angle theta

07:14 CBSE class 10 maths NCERT Solutions Trigonometry Exercise 8.1 Q3. If sin A = 3/4 calculate cos A and tan A.

07:47 Finding the sides of right-angled triangle

08:25 sin is equal to opposite over hypotenuse. Remember as ' SOH '

09:53 cosine of angle theta = side adjacent to angle theta / hypotenuse

Remember as ' CAH ' Cosine equals Adjacent over Hypotenus.

10:28 Tangent of angle theta = side opposite to angle theta / side adjacent to angle theta.Remeber as ' TAO '. Tan is adjacent over

10:41 CBSE class 10 maths NCERT Solutions Trigonometry Exercise 8.1 Q4. Given 15 cot A = 8, find sin A and sec A.

11:10 Naming the sides

11:38 cotangent of angle theta = side adjacent to angle theta / side opposite to angle theta

12:25 Pythagoras Theorem

13:07 Trigonometric Ratio Defination

sine of angle theta = side opposite to angle theta / hypotenuse

sin is equal to opposite over hypotenuse. Remember as ' SOH '

13:26 Trigonometric Ratio Defination 'secant'

secant of angle theta = hypotenuse / side adjacent to angle theta

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